Matematika

Pertanyaan

Tentukan hp dari pesamaan 2 cos 2x + √3 = 0 dan 0°≤ x ≤ 720°

1 Jawaban

  • 2cos2x+√3 = 0
    cos2x = [tex] \frac{-1}{2} \sqrt{3} [/tex]

    - 2x = 150°+k.360°
        x = 75°+k.180°
      *k=0
       x = 75°+0.180°
       x = 75°
      *k=1
       x = 75°+1.180°
       x = 255°
      *k=2
       x = 75°+2.180°
       x = 435°
      *k=3
       x = 75°+3.180
       x = 615°

    - 2x = -150°+k.360
        x = -75°+k.180
      *k=0
       x = -75°+0.180
       x = -75° (tidak memenuhi)
      *k=1
       x = -75°+1.180°
       x = 105°
      *k=2
       x = -75°+2.180°
       x = 285°
      *k=3
       x = -75°+3.180°
       x = 465°
      *k=4
       x = -75°+4.180°
       x = 645°

    HP={75°,105°,255°,285°,435°,465°,615°,645°}

    Semoga membantu, jadikan yg terbaik yaa:)

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