integral 6 (x+4)*5 dx?

∫6(x+4)^5 dx

= 6/(5+1) . (x+4)^(5+1) + c

= 6/6 . (x + 4)^6 + c

= 1 . (x + 4)^6 + c

= (x + 4)^6 + c

∫ 6(x + 4)⁵ dx adalah (x + 4)⁶ + C

Pembahasan

∫ 6(x + 4)⁵ dx

misal

u = x + 4

du = 1

dx = du / 1

∫ 6(x + 4)⁵ dx = 6 . ∫ u⁵ . du

∫ 6(x + 4)⁵ dx = 6 . 1/(5 + 1) . u⁵⁺¹

∫ 6(x + 4)⁵ dx = 6 . 1/6 . u⁶ + C

∫ 6(x + 4)⁵ dx = (x + 4)⁶ + C

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu

Kode: 11.2.10

Kata Kunci: integral substitusi