jawab pakai cara ya pliss tolong beso dikumpul nah. pakai cara ya makasih banya jo

Penyelesaian:

b. [tex] \frac{1}{3} (6x + 9) = \frac{1}{4} (2x + 4)[/tex]
2x + 3 = 1/2.x + 1
3/2.x = -2
3x = -4
x = -4/3

c. 2 - 3(1 - 2x) = 5 - 2(2x + 3)
2 - 3 + 6x = 5 - 4x - 6
-1 + 6x = -4x - 1
6x + 4x = 0
10x = 0
x = 0

d. [tex] \frac{2x - 11}{3} + 5 = \frac{1 + x}{2} - 4[/tex]
[tex] \frac{2x - 11 + 15}{3} = \frac{1 + x - 8}{2} [/tex]
[tex] \frac{2x + 4}{3} = \frac{x - 7}{2} [/tex]
4x + 8 = 3x - 21
x = -29

e. [tex] \frac{4x + 3}{3} + \frac{4}{3} (1 - x) = \frac{6x + 5}{3} [/tex]
4x + 3 + 12/5(1 - x) = 6x + 5    (kedua ruas di kali 3)
4x + 3 + 12/5 - 12/5.x = 6x + 5
8/5.x + 27/5 = 6x + 5
22/5.x = 2/5
22x = 2
x = 1/11