3a-2 pangkat 5 jawaban. berapa ya

[tex](a-b)^{5}= a^{5}-5 a^{4}b+10 a^{3} b^{2}-10 a^{2} b^{3} +5a b^{4} - b^{4} 
[/tex]

maka....

[tex](3a-2)^{5}= (3a)^{5}-5 (3a)^{4}.2+10 (3a)^{3} .2^{2}-10 (3a)^{2} .2^{3} +5(3a) .2^{4} - 2^{4} [/tex]