Cara dan jawabannya ⅔x+6≤8

Materi : Program Linear
Bahasan : Pertidaksamaan Linear
Jawaban : HP = {x | x ≤ 3, x ∈ R}

Langkah - langkah :
(2/3)x + 6 ≤ 8
Hilangkan pecahan :
3(2/3)x + 3(6) ≤ 3(8)
2x + 18 ≤ 24
2x ≤ 24 - 18
2x ≤ 6
x ≤ 3

HP = {x | x ≤ 3, x ∈ R}

⅔x + 6 ≤ 8 (semua dikali 3)
2x + 18 ≤ 24 = 2x ≤ 24-18 = 2x ≤ 6 =

x ≤ 3