Matematika

Pertanyaan

suatu deret geometri diketahui U2 = 40, U5 = 5. tentukansuku ke-8 dan jumlah 5suku pertama

1 Jawaban

  • U2 = 40
    ar = 40

    U5 = 5
    ar^4 = 5

    ar^4 / ar = 5/40
    r^3 = 1/8
    r = 1/2

    ar = 40
    a (1/2) = 40
    a = 80

    U8 = ar^7
    U8 = 80 (1/2)^7
    U8 = 80/128
    U8 = 5/8

    S5 = a (1 - r^n) / 1 - r
    S5 = 80 (1 - (1/2)^5) / 1 - 1/2
    S5 = 80 (1 - (1/32) / 1/2
    S5 = 160 (1 - 1/32)
    S5 = 160 - 5
    S5 = 155

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