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Pertanyaan

hitunglah titik beku larutan 12, 8 gram naftalebc( C4 H8 ) dalam 250 gram benzena. jika titik beku benzena = 5,5° C,, Kf Benzena = 5,10° kg/mol

1 Jawaban

  • ΔTf = Kf.M.i
    Tf°-Tf = [tex]Kf. \frac{grt}{Mrt} .\frac{V}{grp}.i[/tex]
    [tex]5,5-Tf = 5,1.\frac{12,8}{56} . \frac{1000}{250} .1 \\\\ 5,5-Tf = 5,1.\frac{12,8}{56}.4 \\\\ 5,5-Tf = 4,661 \\\\ Tf= 0,839°C[/tex]

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