No 1. Salah satu nilai k yangmemenuhi persamaan k integral 2 (2x-1) dx=4 adalah..... 2. 2 integral 0 (x+3)(2x-1) dx adalah... 3. Hasil dari 2integral 1 (x^2 - 1

1) (2x - 1) dx = 4
x² - x = 4
k² - k - (2² - 2) = 4
k² - k - 2 = 4
k² - k - 6 = 0
(k - 3)(k + 2) = 0
k = 3 atau k = -2
2) (x + 3)(2x - 1)dx
= (2x² + 5x - 3) dx
= (2/3)x³ + (5/2)x² - 3x
= (2/3)(2³) + (5/2)(2)² - 3(2) - {(2/3)0³ + (5/2)0² - 3(0)}
= 16/3 + 20/2 - 6 - {0}
= 16/3 + 10 - 6
= 16/3 + 4
= 16/3 + 12/3
= 28/3
= 9⅓
3) (x² - 1/x²) dx
(x² - x^-2) dx
= ⅓x³ + x^-1
= ⅓x³ + 1/x
= ⅓(2³) + 1/2 - {⅓(1³) + 1/1)}
= 8/3 + 1/2 - {⅓ + 1}
= 8/3 + 1/2 - ⅓ - 1
= 7/3 + 1/2 - 1
= 14/6 + 3/6 - 6/6
= 11/6
= 1(5/6)