Matematika

Pertanyaan

Diket. barisan aritmetika dg U3=21 & U7+U8=69. Tentukan U15

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1 Jawaban

  • U3 = 21
    U7+U8 = 69
    U3 = a+2b = 21
    U7 = a+6b
    U8 = a+7b
    》(a+6b) + (a+7b) = 69
    2a + 13b = 69
    Terus eliminasi antara U3 = 21 dan U7+U8 = 69
    》(2a + 13b) - (a+2b) = 69 - 21
    》(2a + 13b) - 2(a+2b) = 69 - 2(21)
    》(2a + 13b) - (2a+4b) = 69 - 42
    》(2a-2a) + (13b-4b) = 27
    》9b = 27 》b = 27/9 》b = 3
    # a+2b = 21
    # a+2(3) = 21
    # a+6 = 21 》a = 21-6 》a = 15
    Dit: U15 ?
    》U15 = a + (n-1)b
    》U15 = 15 + (15-1)3
    》U15 = 15 + (14)3 》U15 = 15 + 42 = 57

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