Tentukan penyelesaian persamaan nilai mutlak |2x-1| = |x+3|

| 2x - 1 | = | x + 3 |

2x - 1 = x + 3
2x - x = 3 + 1
x = 4

2x - 1 = -(x + 3)
2x - 1 = -x - 3
2x + x = -3 + 1
3x = -2
x = -2/3

Hp = {-2/3 , 4}

|2x-1|=|x+3|
2x-1=x+3 atau 2x-1=-(x+3)
2x-x=3+1. 2x-1=-x-3
x=4. 2x+x=-3+1
3x=-2
x=-2 per 3