8 log 25 dikali 1/5 log 16

8log25 = 2³log5² = 2/3 ²log5
1/5log16 = 5⁻¹log2⁴ = -4/1 ⁵log2 = -4 ⁵log2

⁸log25 x 1/5log16 = 2/3 ²log5 x (-4 ⁵log2)
                             = 2/3. (-4) . ²log5 . ⁵log2
                             = -8/3 . ²log2
                             = -8/3 . 1
                             = -8/3

Materi : Logaritma X SMA

Pembahasan :
⁸log 25 . (1/5)'log 16
= ⁸log 5² . (5¯¹)'log 2⁴
= (2³)'log 5² . (5¯¹)'log 2⁴
= 2/3 ²log 5 . 4/(-1) . ⁵log 2
= 2/3 . (-4) . ²log 5 . ⁵log 2
= -8/3 . ²log 2
= -8/3 . 1
= -8/3