Matematika

Pertanyaan

faktorkanlah bentuk bentuk aljabar berikut
1.2x²+7x+3
2.2x²+5x+3
3.3y²+8y+4
4.5x²+13x+6
5.3y²-8y+4
tolong jwab pake caranya

1 Jawaban

  • 1.2x²+7x+3

    <==> ( 2x+1)(x+3)

    *2x+1 = 0
    2x = -1
    x = - 1/2

    *x+3=0
    x= -3


    2.2x²+5x+3

    <==> (2x+3)(x+1)

    *2x+3 = 0
    2x = -3
    x = - 3/2

    *x+1=0
    x= -1


    3.3y²+8y+4

    <==> (3y+2)(y+2)

    *3y+2 = 0
    3y = -2
    y = - 2/3

    *y+2=0
    y= -2


    4.5x²+13x+6

    <==> (5x+3)(x+2)

    *5x+3 = 0
    5x = -3
    x = - 3/5

    *x+2=0
    x= -2


    5.3y²-8y +4

    <==> (3y-2)(y-2)

    *3y-2 = 0
    3y = 2
    y = 2/3

    *y-2=0
    y = 2

    Semoga membantu


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